moi pour ca j'utilise une API, mais c'est pas un msgbox :
Private Type OPENFILENAME
lStructSize As Long
hWndOwner As Long
hInstance As Long
lpstrFilter As String
lpstrCustomFilter As String
nMaxCustFilter As Long
nFilterIndex As Long
lpstrFile As String
nMaxFile As Long
lpstrFileTitle As String
nMaxFileTitle As Long
lpstrInitialDir As String
lpstrTitle As String
flags As Long
nFileOffset As Integer
nFileExtension As Integer
lpstrDefExt As String
lCustData As Long
lpfnHook As Long
lpTemplateName As String
End Type
Private Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As OPENFILENAME) As Long
ceci correspond à l'API et à un type qui lui est nécessaire.
pour l'appeler :
Dim OFName As OPENFILENAME
With OFName
.lStructSize = Len(OFName)
.hWndOwner = Me.hWnd
.hInstance = App.hInstance
.lpstrFilter = "Document texte (en .txt)" + Chr$(0) + "*.txt" + Chr$(0)
.lpstrFile = Space$(254)
.nMaxFile = 255
.lpstrFileTitle = Space$(254)
.nMaxFileTitle = 255
.lpstrInitialDir = "C:"
.lpstrTitle = "Choix du fichier"
.flags = 0
End With
If GetOpenFileName(OFName) Then
Resultat = Trim$(OFName.lpstrFile)
MsgBox Resultat, vbInformation
End If
la ligne qui commence par .lpstrFilter doit etre modifiée en fonction du type de fichier autorisé.
Houzéf@ - www.123toto.com