c'est un simple source pour upload file to ftp server
program crée par bensoftchlef@gmail.com
alor vous pouvez ajouter des rebriques pour cette source pour crée un logiciel de transfaire des données ou dans une autre application software...
Source / Exemple :
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Net;
using System.IO;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication6
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Upload(string filename)
{
FileInfo fileInf = new FileInfo(filename);
string uri = uri = "ftp://" + textBox2.Text + "/" + fileInf.Name;
FtpWebRequest reqFTP;
// Create FtpWebRequest object from the Uri provided
reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://" + textBox2.Text + "/" + filename));
// Provide the WebPermission Credintials
reqFTP.Credentials = new NetworkCredential(textBox3.Text, maskedTextBox1.Text);
// By default KeepAlive is true, where the control connection is not closed
// after a command is executed.
reqFTP.KeepAlive = false;
// Specify the command to be executed.
reqFTP.Method = WebRequestMethods.Ftp.UploadFile;
// Specify the data transfer type.
reqFTP.UseBinary = true;
// Notify the server about the size of the uploaded file
reqFTP.ContentLength = fileInf.Length;
// The buffer size is set to 2kb
int buffLength = 2048;
byte[] buff = new byte[buffLength];
int contentLen;
// Opens a file stream (System.IO.FileStream) to read the file to be uploaded
FileStream fs = fileInf.OpenRead();
try
{
// Stream to which the file to be upload is written
Stream strm = reqFTP.GetRequestStream();
// Read from the file stream 2kb at a time
contentLen = fs.Read(buff, 0, buffLength);
// Till Stream content ends
while (contentLen != 0)
{
// Write Content from the file stream to the FTP Upload Stream
strm.Write(buff, 0, contentLen);
contentLen = fs.Read(buff, 0, buffLength);
}
// Close the file stream and the Request Stream
strm.Close();
fs.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message, "Upload Error");
}
}
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.ShowDialog();
}
private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
{
textBox1.Text = openFileDialog1.FileName;
}
private void button2_Click(object sender, EventArgs e)
{
Upload(textBox1.Text);
}
}
}
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